Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If a 1 (> 0), a 2 , a 3 , a 4 , a 5 are in a G.P., a 2 + a 4 = 2a 3 + 1 and 3a 2 + a 3 = 2a 4 , then a 2 + a 4 + 2a 5 is equal to
Text Solution
Verified by ExpertsThe correct answer is:
40
(40)
a 1 > 0, a 2 , a 3 , a 4 , a 5 
G.P.
3a 2 + a 3 = 2a 4
3ar + ar 2 = 2ar 3
3 + r=2r 2
2r 2 -r-3 = 0
r = - 1 & r = 
a 2 + a 4 = 2a 3 + 1
ar + ar 3 = 2ar 2 + 1
a (r + r 3 – 2r 2 ) = 1
When r = -1, a = 
(rejected, a 1 > 0)
(selected)
Now
a 2 + a 4 + 2a 5
= 4 + 9 + 27 = 40
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